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iOS禁止所有输入法表情的方法

2018-10-04 00:00:00 发布   753 浏览  
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本文实例为大家分享了iOS禁止所有输入法表情的具体代码,供大家参考,具体内容如下

- (BOOL)textView:(UITextView *)textView shouldChangeTextInRange:(NSRange)range replacementText:(NSString *)text {
  //禁止所有输入法的表情
  if ([self isContainsTwoEmoji:text]) {
    return NO;
  }
  return YES;
}

//判断是否是表情字符

- (BOOL)isContainsTwoEmoji:(NSString *)string {
  __block BOOL isEomji = NO;
  [string enumerateSubstringsInRange:NSMakeRange(0, [string length]) options:NSStringEnumerationByComposedCharacterSequences usingBlock:
   ^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {
     const unichar hs = [substring characterAtIndex:0];
     //     NSLog(@"hs++++++++%04x",hs);
     if (0xd800 <= hs && hs <= 0xdbff) {
       if (substring.length > 1) {
         const unichar ls = [substring characterAtIndex:1];
         const int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;
         if (0x1d000 <= uc && uc <= 0x1f77f)
         {
           isEomji = YES;
         }
         //         NSLog(@"uc++++++++%04x",uc);
       }
     } else if (substring.length > 1) {
       const unichar ls = [substring characterAtIndex:1];
       if (ls == 0x20e3|| ls ==0xfe0f) {
         isEomji = YES;
       }
       //       NSLog(@"ls++++++++%04x",ls);
     } else {
       if (0x2100 <= hs && hs <= 0x27ff && hs != 0x263b) {
         isEomji = YES;
       } else if (0x2B05 <= hs && hs <= 0x2b07) {
         isEomji = YES;
       } else if (0x2934 <= hs && hs <= 0x2935) {
         isEomji = YES;
       } else if (0x3297 <= hs && hs <= 0x3299) {
         isEomji = YES;
       } else if (hs == 0xa9 || hs == 0xae || hs == 0x303d || hs == 0x3030 || hs == 0x2b55 || hs == 0x2b1c || hs == 0x2b1b || hs == 0x2b50|| hs == 0x231a ) {
         isEomji = YES;
       }
     }
   }];
  return isEomji;
}

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持脚本之家。

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