Erlo

mysql(5.6及以下)解析json

2019-07-18 10:04:03 发布   524 浏览  
页面报错/反馈
收藏 点赞

转自:https://blog.csdn.net/weixin_33979203/article/details/87621768

#json解析函数       
DELIMITER $$
DROP FUNCTION IF EXISTS `json_extract_c`$$
CREATE FUNCTION `json_extract_c`(
details TEXT,
required_field VARCHAR (255)
) RETURNS TEXT CHARSET latin1
BEGIN
SET details = SUBSTRING_INDEX(details, "{", -1);
SET details = SUBSTRING_INDEX(details, "}", 1);
RETURN TRIM(
    BOTH '"' FROM SUBSTRING_INDEX(
        SUBSTRING_INDEX(
            SUBSTRING_INDEX(
                details,
                CONCAT(
'"',
                    SUBSTRING_INDEX(required_field,'$.', -1),
'":'
                ),
-1
            ),
',"',
1
        ),
':',
-1
    )
) ;
END$$
DELIMITER ;
example:
select json_extract_c(json, "$.totalDays"), json from item limit 100;

自测
CREATE TABLE `json_test` (
  `id` int(11) DEFAULT NULL,
  `person_desc` text COLLATE utf8mb4_unicode_ci
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_unicode_ci;


insert INTO json_test values(2,'{"firstName":"Sergei","lastName":"Rachmaninoff","instrument":"piano"}');
SELECT id,json_extract_c(person_desc,'$.lastName') as "keys" FROM json_test;

 

 改进,再找不到key,返回''值,之前的是在找不到的情况下,查找到第一的值。


CREATE
DEFINER=`zhangfen`@`%` FUNCTION `json_extract_c`( details TEXT, required_field VARCHAR (255) ) RETURNS text CHARSET latin1 BEGIN SET details = SUBSTRING_INDEX(details, "{", -1); SET details = SUBSTRING_INDEX(details, "}", 1); RETURN TRIM( BOTH '"' FROM SUBSTRING_INDEX( SUBSTRING_INDEX( SUBSTRING_INDEX( CONCAT('"":"",',details), CONCAT( '"', SUBSTRING_INDEX(required_field,'$.', -1), '":' ), -1 ), ',"', 1 ), ':', -1 ) ) ; END

 

登录查看全部

参与评论

评论留言

还没有评论留言,赶紧来抢楼吧~~

手机查看

返回顶部

给这篇文章打个标签吧~

棒极了 糟糕透顶 好文章 PHP JAVA JS 小程序 Python SEO MySql 确认